What are the solutions to the equation x^2-10x=39 ?

The solutions to the equation x^2-10x=39 are x=13,x=-3

Find the zeros of x^2-10x=39

The zeros of x^2-10x=39 are x=13,x=-3

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x^{2} - 10 x = 39

x = 13, x = - 3

Solution steps

x^{2} - 10 x = 39

Move

39

to the left side

x^{2} - 10 x - 39 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot ( - 39 )}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot (- 39) = 16

x_{1, 2} = \frac{- ( - 10 ) \pm 16}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 16}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 16}{2 \cdot 1}

x = \frac{- ( - 10 ) + 16}{2 \cdot 1} : 13

x = \frac{- ( - 10 ) - 16}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 13, x = - 3

x^{2} - 10 x = 40

x^{2} - 10 x = 25

256 x^{2} = 16 x

6^{2} = x^{2} + x^{2}

1 - 9 x^{2} = 0

What are the solutions to the equation x^2-10x=39 ?
The solutions to the equation x^2-10x=39 are x=13,x=-3
Find the zeros of x^2-10x=39
The zeros of x^2-10x=39 are x=13,x=-3