What are the solutions to the equation 9x^2-4x-7=0 ?

The solutions to the equation 9x^2-4x-7=0 are x=(2+sqrt(67))/9 ,x=(2-sqrt(67))/9

Find the zeros of 9x^2-4x-7=0

The zeros of 9x^2-4x-7=0 are x=(2+sqrt(67))/9 ,x=(2-sqrt(67))/9

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9 x^{2} - 4 x - 7 = 0

x = \frac{2 + 67}{9}, x = \frac{2 - 67}{9}

Decimal

x = 1.13170 \dots, x = - 0.68726 \dots

Solution steps

9 x^{2} - 4 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 9 ( - 7 )}{2 \cdot 9}

(- 4)^{2} - 4 \cdot 9 (- 7) = 267

x_{1, 2} = \frac{- ( - 4 ) \pm 2 67}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 67}{2 \cdot 9}, x_{2} = \frac{- ( - 4 ) - 2 67}{2 \cdot 9}

x = \frac{- ( - 4 ) + 2 67}{2 \cdot 9} : \frac{2 + 67}{9}

x = \frac{- ( - 4 ) - 2 67}{2 \cdot 9} : \frac{2 - 67}{9}

The solutions to the quadratic equation are:

x = \frac{2 + 67}{9}, x = \frac{2 - 67}{9}

x^{2} - 4 x - 30 = 0

16 p^{2} - 9 = 0

x^{2} + 12 x + 100 = 0

6 x^{2} + 96 = 0

x, 3 (13 x^{2} - 4 y^{2}) = 15 y^{2} - 2 x^{2}

What are the solutions to the equation 9x^2-4x-7=0 ?
The solutions to the equation 9x^2-4x-7=0 are x=(2+sqrt(67))/9 ,x=(2-sqrt(67))/9
Find the zeros of 9x^2-4x-7=0
The zeros of 9x^2-4x-7=0 are x=(2+sqrt(67))/9 ,x=(2-sqrt(67))/9