What are the solutions to the equation 1/2 (x-1)^2-4=-1 ?

The solutions to the equation 1/2 (x-1)^2-4=-1 are x=sqrt(6)+1,x=-sqrt(6)+1

Find the zeros of 1/2 (x-1)^2-4=-1

The zeros of 1/2 (x-1)^2-4=-1 are x=sqrt(6)+1,x=-sqrt(6)+1

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\frac{1}{2} (x - 1)^{2} - 4 = - 1

x = 6 + 1, x = - 6 + 1

Decimal Notation

x = 3.44948 \dots, x = - 1.44948 \dots

Solution steps

\frac{1}{2} (x - 1)^{2} - 4 = - 1

Move

4

to the right side

\frac{1}{2} (x - 1)^{2} = 3

Multiply both sides by

2

(x - 1)^{2} = 6

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = 6 : x = 6 + 1

Solve

x - 1 = - 6 : x = - 6 + 1

The solutions to the quadratic equation are:

x = 6 + 1, x = - 6 + 1

12 - x^{2} = x^{2} - 2 x

a^{2} - 5 a - 14 = 0

2 x^{2} = x - 4

x, x^{2} + 49 = 0

n^{2} + 2 n - 3 = 0

What are the solutions to the equation 1/2 (x-1)^2-4=-1 ?
The solutions to the equation 1/2 (x-1)^2-4=-1 are x=sqrt(6)+1,x=-sqrt(6)+1
Find the zeros of 1/2 (x-1)^2-4=-1
The zeros of 1/2 (x-1)^2-4=-1 are x=sqrt(6)+1,x=-sqrt(6)+1