What are the solutions to the equation u^2+10u+24=0 ?

The solutions to the equation u^2+10u+24=0 are u=-4,u=-6

Find the zeros of u^2+10u+24=0

The zeros of u^2+10u+24=0 are u=-4,u=-6

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u^{2} + 10 u + 24 = 0

u = - 4, u = - 6

Solution steps

u^{2} + 10 u + 24 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 24 = 2

u_{1, 2} = \frac{- 10 \pm 2}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- 10 + 2}{2 \cdot 1}, u_{2} = \frac{- 10 - 2}{2 \cdot 1}

u = \frac{- 10 + 2}{2 \cdot 1} : - 4

u = \frac{- 10 - 2}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

u = - 4, u = - 6

x^{2} - 9 x - 5 = 23

16 x^{2} + 16 x + 3 = 0

x, (y - 4)^{2} + 20 (x + 3)^{2} = 0

x^{2} + 1 2^{2} = 1 4^{2}

15 x^{2} + 2 x + 1 = 0

What are the solutions to the equation u^2+10u+24=0 ?
The solutions to the equation u^2+10u+24=0 are u=-4,u=-6
Find the zeros of u^2+10u+24=0
The zeros of u^2+10u+24=0 are u=-4,u=-6