What are the solutions to the equation x^2+64x-32000=0 ?

The solutions to the equation x^2+64x-32000=0 are x=16(sqrt(129)-2),x=-16(2+sqrt(129))

Find the zeros of x^2+64x-32000=0

The zeros of x^2+64x-32000=0 are x=16(sqrt(129)-2),x=-16(2+sqrt(129))

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x^{2} + 64 x - 32000 = 0

x = 16 (129 - 2), x = - 16 (2 + 129)

Decimal Notation

x = 149.72506 \dots, x = - 213.72506 \dots

Solution steps

x^{2} + 64 x - 32000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 64 \pm 6 4 ^{2} - 4 \cdot 1 \cdot ( - 32000 )}{2 \cdot 1}

6 4^{2} - 4 \cdot 1 \cdot (- 32000) = 32129

x_{1, 2} = \frac{- 64 \pm 32 129}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 64 + 32 129}{2 \cdot 1}, x_{2} = \frac{- 64 - 32 129}{2 \cdot 1}

x = \frac{- 64 + 32 129}{2 \cdot 1} : 16 (129 - 2)

x = \frac{- 64 - 32 129}{2 \cdot 1} : - 16 (2 + 129)

The solutions to the quadratic equation are:

x = 16 (129 - 2), x = - 16 (2 + 129)

3 - x^{2} = x + 1

m^{2} - 6 m - 9 = 0

3 u^{2} = 12 u - 3

5 x^{2} + 15 = - 28 x

2 x^{2} - 4 x - 11 = 0

What are the solutions to the equation x^2+64x-32000=0 ?
The solutions to the equation x^2+64x-32000=0 are x=16(sqrt(129)-2),x=-16(2+sqrt(129))
Find the zeros of x^2+64x-32000=0
The zeros of x^2+64x-32000=0 are x=16(sqrt(129)-2),x=-16(2+sqrt(129))