What are the solutions to the equation -(x-3)^2+4=0 ?

The solutions to the equation -(x-3)^2+4=0 are x=5,x=1

Find the zeros of -(x-3)^2+4=0

The zeros of -(x-3)^2+4=0 are x=5,x=1

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- (x - 3)^{2} + 4 = 0

x = 5, x = 1

Solution steps

- (x - 3)^{2} + 4 = 0

Move

4

to the right side

- (x - 3)^{2} = - 4

Divide both sides by

- 1

(x - 3)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 4 : x = 5

Solve

x - 3 = - 4 : x = 1

The solutions to the quadratic equation are:

x = 5, x = 1

(a x^{2} + 3 b x + 8) + (2 x^{2} - 4 x + c) = 5 x^{2} - 2 x + 3

n^{2} - 24 n

x^{2} - 7 x = - 1

y^{2} - 5 y - 84 = 0

\frac{x ^{2}}{2} - \frac{7 x}{20} = \frac{3}{10}

What are the solutions to the equation -(x-3)^2+4=0 ?
The solutions to the equation -(x-3)^2+4=0 are x=5,x=1
Find the zeros of -(x-3)^2+4=0
The zeros of -(x-3)^2+4=0 are x=5,x=1