What are the solutions to the equation 7r^2+84=-49r ?

The solutions to the equation 7r^2+84=-49r are r=-3,r=-4

Find the zeros of 7r^2+84=-49r

The zeros of 7r^2+84=-49r are r=-3,r=-4

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7 r^{2} + 84 = - 49 r

r = - 3, r = - 4

Solution steps

7 r^{2} + 84 = - 49 r

Move

49 r

to the left side

7 r^{2} + 84 + 49 r = 0

Write in the standard form

a x^{2} + b x + c = 0

7 r^{2} + 49 r + 84 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 49 \pm 4 9 ^{2} - 4 \cdot 7 \cdot 84}{2 \cdot 7}

4 9^{2} - 4 \cdot 7 \cdot 84 = 7

r_{1, 2} = \frac{- 49 \pm 7}{2 \cdot 7}

Separate the solutions

r_{1} = \frac{- 49 + 7}{2 \cdot 7}, r_{2} = \frac{- 49 - 7}{2 \cdot 7}

r = \frac{- 49 + 7}{2 \cdot 7} : - 3

r = \frac{- 49 - 7}{2 \cdot 7} : - 4

The solutions to the quadratic equation are:

r = - 3, r = - 4

y^{2} + 16 y

x^{2} - 11 x - 12 = 0

6 x^{2} + 19 x + 8 = 0

3 s^{2} + 36 = 0

x^{2} - 11 x + 20 = - 4

What are the solutions to the equation 7r^2+84=-49r ?
The solutions to the equation 7r^2+84=-49r are r=-3,r=-4
Find the zeros of 7r^2+84=-49r
The zeros of 7r^2+84=-49r are r=-3,r=-4