What are the solutions to the equation completesquare x^2+x+5/4 ?

The solutions to the equation completesquare x^2+x+5/4 are (x+1/2)^2+1

Find the zeros of completesquare x^2+x+5/4

The zeros of completesquare x^2+x+5/4 are (x+1/2)^2+1

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complete the square

x^{2} + x + \frac{5}{4}

(x + \frac{1}{2})^{2} + 1

Solution steps

x^{2} + x + \frac{5}{4}

Write

x^{2} + x + \frac{5}{4}

in the form:

x^{2} + 2 a x + a^{2}

2 a = 1 : a = \frac{1}{2}

Add and subtract

(\frac{1}{2})^{2}

x^{2} + x + \frac{5}{4} + (\frac{1}{2})^{2} - (\frac{1}{2})^{2}

x^{2} + 2 a x + a^{2} = (x + a)^{2}

x^{2} + 1 x + (\frac{1}{2})^{2} = (x + \frac{1}{2})^{2}

(x + \frac{1}{2})^{2} + \frac{5}{4} - (\frac{1}{2})^{2}

Simplify

(x + \frac{1}{2})^{2} + 1

(x - 1)^{2} + 4 = 0

x, y = 24 - 6 x^{2}

(x + 7)^{2} + 28 = 0

3 x^{2} - 8 x - 9 = 0

x^{2} - 12 = - 2 x

What are the solutions to the equation completesquare x^2+x+5/4 ?
The solutions to the equation completesquare x^2+x+5/4 are (x+1/2)^2+1
Find the zeros of completesquare x^2+x+5/4
The zeros of completesquare x^2+x+5/4 are (x+1/2)^2+1