What are the solutions to the equation (x+9)(2x+1)=100 ?

The solutions to the equation (x+9)(2x+1)=100 are x= 7/2 ,x=-13

Find the zeros of (x+9)(2x+1)=100

The zeros of (x+9)(2x+1)=100 are x= 7/2 ,x=-13

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(x + 9) (2 x + 1) = 100

x = \frac{7}{2}, x = - 13

Decimal Notation

x = 3.5, x = - 13

Solution steps

(x + 9) (2 x + 1) = 100

Expand

(x + 9) (2 x + 1) : 2 x^{2} + 19 x + 9

2 x^{2} + 19 x + 9 = 100

Move

100

to the left side

2 x^{2} + 19 x - 91 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 \cdot 2 ( - 91 )}{2 \cdot 2}

1 9^{2} - 4 \cdot 2 (- 91) = 33

x_{1, 2} = \frac{- 19 \pm 33}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 19 + 33}{2 \cdot 2}, x_{2} = \frac{- 19 - 33}{2 \cdot 2}

x = \frac{- 19 + 33}{2 \cdot 2} : \frac{7}{2}

x = \frac{- 19 - 33}{2 \cdot 2} : - 13

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = - 13

6 x^{2} - 24 x = 30

0 = - 16 t^{2} + 12 t + 120

(x + 1) (2 x + 3) (3 x + 4) = (6 x^{2} + 5) (x - 3)

4 y^{2} + y - 3 = 0

s^{2} + 6 s + 1 = 0

What are the solutions to the equation (x+9)(2x+1)=100 ?
The solutions to the equation (x+9)(2x+1)=100 are x= 7/2 ,x=-13
Find the zeros of (x+9)(2x+1)=100
The zeros of (x+9)(2x+1)=100 are x= 7/2 ,x=-13