What are the solutions to the equation g^2+2g+1=0 ?

The solutions to the equation g^2+2g+1=0 are g=-1

Find the zeros of g^2+2g+1=0

The zeros of g^2+2g+1=0 are g=-1

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g^{2} + 2 g + 1 = 0

g = - 1

Solution steps

g^{2} + 2 g + 1 = 0

Solve with the quadratic formula

g_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 1 = 0

g_{1, 2} = \frac{- 2 \pm 0}{2 \cdot 1}

g = \frac{- 2}{2 \cdot 1}

\frac{- 2}{2 \cdot 1} = - 1

g = - 1

The solution to the quadratic equation is:

g = - 1

- 3 x^{2} + 15 x + 11 = 0

- 3 x^{2} - 24 x - 19 = 0

7 x^{2} + 13 x - 2 = 0

2 x^{2} - 18 = 46

2 x^{2} - 16 x + 20 = 0

What are the solutions to the equation g^2+2g+1=0 ?
The solutions to the equation g^2+2g+1=0 are g=-1
Find the zeros of g^2+2g+1=0
The zeros of g^2+2g+1=0 are g=-1