What are the solutions to the equation 1.3x^2+7x=0 ?

The solutions to the equation 1.3x^2+7x=0 are x=0,x=-70/13

Find the zeros of 1.3x^2+7x=0

The zeros of 1.3x^2+7x=0 are x=0,x=-70/13

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1.3 x^{2} + 7 x = 0

x = 0, x = - \frac{70}{13}

Decimal Notation

x = 0, x = - 5.38461 \dots

Solution steps

1.3 x^{2} + 7 x = 0

Multiply both sides by

10

13 x^{2} + 70 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 70 \pm 7 0 ^{2} - 4 \cdot 13 \cdot 0}{2 \cdot 13}

7 0^{2} - 4 \cdot 13 \cdot 0 = 70

x_{1, 2} = \frac{- 70 \pm 70}{2 \cdot 13}

Separate the solutions

x_{1} = \frac{- 70 + 70}{2 \cdot 13}, x_{2} = \frac{- 70 - 70}{2 \cdot 13}

x = \frac{- 70 + 70}{2 \cdot 13} : 0

x = \frac{- 70 - 70}{2 \cdot 13} : - \frac{70}{13}

The solutions to the quadratic equation are:

x = 0, x = - \frac{70}{13}

4 x^{2} - 90 = 10

x, 2 x^{2} + y^{2} + 3 \cdot x \cdot y = 1

x^{2} - 10 x - 1 = 0

(2 x + 3)^{2} - 4 = 0

- 3 x + 18 = x^{2}

What are the solutions to the equation 1.3x^2+7x=0 ?
The solutions to the equation 1.3x^2+7x=0 are x=0,x=-70/13
Find the zeros of 1.3x^2+7x=0
The zeros of 1.3x^2+7x=0 are x=0,x=-70/13