What are the solutions to the equation 2z^2-6=0 ?

The solutions to the equation 2z^2-6=0 are z=sqrt(3),z=-sqrt(3)

Find the zeros of 2z^2-6=0

The zeros of 2z^2-6=0 are z=sqrt(3),z=-sqrt(3)

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2 z^{2} - 6 = 0

z = 3, z = - 3

Decimal Notation

z = 1.73205 \dots, z = - 1.73205 \dots

Solution steps

2 z^{2} - 6 = 0

Move

6

to the right side

2 z^{2} = 6

Divide both sides by

2

z^{2} = 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

z = 3, z = - 3

- 5 x^{2} + 10 x + 8 = 7 x^{2} + 7 x + 5

m, h = m (10) + (\frac{1 + m ^{2}}{40}) \cdot 100

x^{2} + 4 x + 12 = 9

7 x^{2} + 5 x + 1 = 0

24 x^{2} - 60 x - 144 = 0

What are the solutions to the equation 2z^2-6=0 ?
The solutions to the equation 2z^2-6=0 are z=sqrt(3),z=-sqrt(3)
Find the zeros of 2z^2-6=0
The zeros of 2z^2-6=0 are z=sqrt(3),z=-sqrt(3)