What are the solutions to the equation -k^2-65k+720=0 ?

The solutions to the equation -k^2-65k+720=0 are k=-(65+7sqrt(145))/2 ,k=(7sqrt(145)-65)/2

Find the zeros of -k^2-65k+720=0

The zeros of -k^2-65k+720=0 are k=-(65+7sqrt(145))/2 ,k=(7sqrt(145)-65)/2

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- k^{2} - 65 k + 720 = 0

k = - \frac{65 + 7 145}{2}, k = \frac{7 145 - 65}{2}

Decimal Notation

k = - 74.64558 \dots, k = 9.64558 \dots

Solution steps

- k^{2} - 65 k + 720 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 65 ) \pm ( - 65 ) ^{2} - 4 ( - 1 ) \cdot 720}{2 ( - 1 )}

(- 65)^{2} - 4 (- 1) \cdot 720 = 7145

k_{1, 2} = \frac{- ( - 65 ) \pm 7 145}{2 ( - 1 )}

Separate the solutions

k_{1} = \frac{- ( - 65 ) + 7 145}{2 ( - 1 )}, k_{2} = \frac{- ( - 65 ) - 7 145}{2 ( - 1 )}

k = \frac{- ( - 65 ) + 7 145}{2 ( - 1 )} : - \frac{65 + 7 145}{2}

k = \frac{- ( - 65 ) - 7 145}{2 ( - 1 )} : \frac{7 145 - 65}{2}

The solutions to the quadratic equation are:

k = - \frac{65 + 7 145}{2}, k = \frac{7 145 - 65}{2}

- 16 x^{2} + 85 x = 0

x^{2} - 7 x = 0

3 x^{2} - 42 x = 120

x, G = 3 x^{2} y - 2 x z^{2}

(2 x + 3)^{2} + 3 x (2 x + 1) = 0

What are the solutions to the equation -k^2-65k+720=0 ?
The solutions to the equation -k^2-65k+720=0 are k=-(65+7sqrt(145))/2 ,k=(7sqrt(145)-65)/2
Find the zeros of -k^2-65k+720=0
The zeros of -k^2-65k+720=0 are k=-(65+7sqrt(145))/2 ,k=(7sqrt(145)-65)/2