What are the solutions to the equation 6x^2-x=2 ?

The solutions to the equation 6x^2-x=2 are x= 2/3 ,x=-1/2

Find the zeros of 6x^2-x=2

The zeros of 6x^2-x=2 are x= 2/3 ,x=-1/2

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6 x^{2} - x = 2

x = \frac{2}{3}, x = - \frac{1}{2}

Solution steps

6 x^{2} - x = 2

Move

2

to the left side

6 x^{2} - x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 6 ( - 2 )}{2 \cdot 6}

(- 1)^{2} - 4 \cdot 6 (- 2) = 7

x_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 6}, x_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 6}

x = \frac{- ( - 1 ) + 7}{2 \cdot 6} : \frac{2}{3}

x = \frac{- ( - 1 ) - 7}{2 \cdot 6} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - \frac{1}{2}

4 \cdot 3 + (5 - 2 (8 + 4)) + 6

\frac{7 + 4 i}{4 + i}

∣ b + 6 ∣ - 3 = 4

3 x^{2} - 10 = - 5

p^{2} - 36

What are the solutions to the equation 6x^2-x=2 ?
The solutions to the equation 6x^2-x=2 are x= 2/3 ,x=-1/2
Find the zeros of 6x^2-x=2
The zeros of 6x^2-x=2 are x= 2/3 ,x=-1/2