What are the solutions to the equation x^{(2)}-3x+2=e^{(3)} ?

The solutions to the equation x^{(2)}-3x+2=e^{(3)} are x=(3+sqrt(4e^3+1))/2 ,x=(3-sqrt(4e^3+1))/2

Find the zeros of x^{(2)}-3x+2=e^{(3)}

The zeros of x^{(2)}-3x+2=e^{(3)} are x=(3+sqrt(4e^3+1))/2 ,x=(3-sqrt(4e^3+1))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{(2)} - 3 x + 2 = e^{(3)}

x = \frac{3 + 4 e ^{3} + 1}{2}, x = \frac{3 - 4 e ^{3} + 1}{2}

Decimal Notation

x = 6.00949 \dots, x = - 3.00949 \dots

Solution steps

x^{(2)} - 3 x + 2 = e^{(3)}

Refine

x^{2} - 3 x + 2 = e^{3}

Move

e^{3}

to the left side

x^{2} - 3 x + 2 - e^{3} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( 2 - e ^{3} )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (2 - e^{3}) = 4 e^{3} + 1

x_{1, 2} = \frac{- ( - 3 ) \pm 4 e ^{3} + 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 4 e ^{3} + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 4 e ^{3} + 1}{2 \cdot 1}

x = \frac{- ( - 3 ) + 4 e ^{3} + 1}{2 \cdot 1} : \frac{3 + 4 e ^{3} + 1}{2}

x = \frac{- ( - 3 ) - 4 e ^{3} + 1}{2 \cdot 1} : \frac{3 - 4 e ^{3} + 1}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 4 e ^{3} + 1}{2}, x = \frac{3 - 4 e ^{3} + 1}{2}

z, x^{2} + y^{2} + (z - 1)^{2} = 1

x, y = \frac{1}{4} x^{2}

x^{2} - 5 + 4 = 0

- 6 x^{2} + 276 x - 2160 = 0

2 y^{2} - 4 y = 0

What are the solutions to the equation x^{(2)}-3x+2=e^{(3)} ?
The solutions to the equation x^{(2)}-3x+2=e^{(3)} are x=(3+sqrt(4e^3+1))/2 ,x=(3-sqrt(4e^3+1))/2
Find the zeros of x^{(2)}-3x+2=e^{(3)}
The zeros of x^{(2)}-3x+2=e^{(3)} are x=(3+sqrt(4e^3+1))/2 ,x=(3-sqrt(4e^3+1))/2