What are the solutions to the equation -3x^2+8x-3=0 ?

The solutions to the equation -3x^2+8x-3=0 are x=(4-sqrt(7))/3 ,x=(4+sqrt(7))/3

Find the zeros of -3x^2+8x-3=0

The zeros of -3x^2+8x-3=0 are x=(4-sqrt(7))/3 ,x=(4+sqrt(7))/3

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- 3 x^{2} + 8 x - 3 = 0

x = \frac{4 - 7}{3}, x = \frac{4 + 7}{3}

Decimal Notation

x = 0.45141 \dots, x = 2.21525 \dots

Solution steps

- 3 x^{2} + 8 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 3 ) ( - 3 )}{2 ( - 3 )}

8^{2} - 4 (- 3) (- 3) = 27

x_{1, 2} = \frac{- 8 \pm 2 7}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 8 + 2 7}{2 ( - 3 )}, x_{2} = \frac{- 8 - 2 7}{2 ( - 3 )}

x = \frac{- 8 + 2 7}{2 ( - 3 )} : \frac{4 - 7}{3}

x = \frac{- 8 - 2 7}{2 ( - 3 )} : \frac{4 + 7}{3}

The solutions to the quadratic equation are:

x = \frac{4 - 7}{3}, x = \frac{4 + 7}{3}

25 = - 4.9 t^{2} + 20 t + 20

lo g_{10} (5) (4 x^{2} + 4) - lo g_{10} (5) (x + 6) = 1

60 = - 4.9 t^{2} + 20 t + 50

(30 - \frac{2}{3} r)^{2} = 100

s^{2} + 8 s + 16

What are the solutions to the equation -3x^2+8x-3=0 ?
The solutions to the equation -3x^2+8x-3=0 are x=(4-sqrt(7))/3 ,x=(4+sqrt(7))/3
Find the zeros of -3x^2+8x-3=0
The zeros of -3x^2+8x-3=0 are x=(4-sqrt(7))/3 ,x=(4+sqrt(7))/3