What are the solutions to the equation 2x^2-6x+15=0 ?

The solutions to the equation 2x^2-6x+15=0 are x= 3/2+i(sqrt(21))/2 ,x= 3/2-i(sqrt(21))/2

Find the zeros of 2x^2-6x+15=0

The zeros of 2x^2-6x+15=0 are x= 3/2+i(sqrt(21))/2 ,x= 3/2-i(sqrt(21))/2

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2 x^{2} - 6 x + 15 = 0

x = \frac{3}{2} + i \frac{21}{2}, x = \frac{3}{2} - i \frac{21}{2}

Solution steps

2 x^{2} - 6 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 \cdot 15}{2 \cdot 2}

Simplify

(- 6)^{2} - 4 \cdot 2 \cdot 15 : 221 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 21 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 21 i}{2 \cdot 2}, x_{2} = \frac{- ( - 6 ) - 2 21 i}{2 \cdot 2}

x = \frac{- ( - 6 ) + 2 21 i}{2 \cdot 2} : \frac{3}{2} + i \frac{21}{2}

x = \frac{- ( - 6 ) - 2 21 i}{2 \cdot 2} : \frac{3}{2} - i \frac{21}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} + i \frac{21}{2}, x = \frac{3}{2} - i \frac{21}{2}

(x - 2)^{2} + x (x + 1) = 24

x, x^{2} + k x + k = x - 2

3 x^{2} + 12 x - 15 = 0

3 y^{2} - 33 y = - 54

1 x^{2} + 2 x - 3 = 0

What are the solutions to the equation 2x^2-6x+15=0 ?
The solutions to the equation 2x^2-6x+15=0 are x= 3/2+i(sqrt(21))/2 ,x= 3/2-i(sqrt(21))/2
Find the zeros of 2x^2-6x+15=0
The zeros of 2x^2-6x+15=0 are x= 3/2+i(sqrt(21))/2 ,x= 3/2-i(sqrt(21))/2