What are the solutions to the equation 7x^2-4x=-1 ?

The solutions to the equation 7x^2-4x=-1 are x= 2/7+i(sqrt(3))/7 ,x= 2/7-i(sqrt(3))/7

Find the zeros of 7x^2-4x=-1

The zeros of 7x^2-4x=-1 are x= 2/7+i(sqrt(3))/7 ,x= 2/7-i(sqrt(3))/7

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7 x^{2} - 4 x = - 1

x = \frac{2}{7} + i \frac{3}{7}, x = \frac{2}{7} - i \frac{3}{7}

Solution steps

7 x^{2} - 4 x = - 1

Move

1

to the left side

7 x^{2} - 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 7 \cdot 1}{2 \cdot 7}

Simplify

(- 4)^{2} - 4 \cdot 7 \cdot 1 : 23 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 3 i}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 3 i}{2 \cdot 7}, x_{2} = \frac{- ( - 4 ) - 2 3 i}{2 \cdot 7}

x = \frac{- ( - 4 ) + 2 3 i}{2 \cdot 7} : \frac{2}{7} + i \frac{3}{7}

x = \frac{- ( - 4 ) - 2 3 i}{2 \cdot 7} : \frac{2}{7} - i \frac{3}{7}

The solutions to the quadratic equation are:

x = \frac{2}{7} + i \frac{3}{7}, x = \frac{2}{7} - i \frac{3}{7}

x, 9 x^{2} - 6 x y + y^{2} - 12 x + 4 y + 4 = 0

x, x^{2} ln (y) + e^{y^{2}} = 25 + y

3 x^{2} - 2 x + 6

3 x^{2} - 2 x + 5

6 x^{2} - 17 x - 14 = 0

What are the solutions to the equation 7x^2-4x=-1 ?
The solutions to the equation 7x^2-4x=-1 are x= 2/7+i(sqrt(3))/7 ,x= 2/7-i(sqrt(3))/7
Find the zeros of 7x^2-4x=-1
The zeros of 7x^2-4x=-1 are x= 2/7+i(sqrt(3))/7 ,x= 2/7-i(sqrt(3))/7