What are the solutions to the equation m^2-12m+26=0 ?

The solutions to the equation m^2-12m+26=0 are m=6+sqrt(10),m=6-sqrt(10)

Find the zeros of m^2-12m+26=0

The zeros of m^2-12m+26=0 are m=6+sqrt(10),m=6-sqrt(10)

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m^{2} - 12 m + 26 = 0

m = 6 + 10, m = 6 - 10

Decimal Notation

m = 9.16227 \dots, m = 2.83772 \dots

Solution steps

m^{2} - 12 m + 26 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 26}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 26 = 210

m_{1, 2} = \frac{- ( - 12 ) \pm 2 10}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 12 ) + 2 10}{2 \cdot 1}, m_{2} = \frac{- ( - 12 ) - 2 10}{2 \cdot 1}

m = \frac{- ( - 12 ) + 2 10}{2 \cdot 1} : 6 + 10

m = \frac{- ( - 12 ) - 2 10}{2 \cdot 1} : 6 - 10

The solutions to the quadratic equation are:

m = 6 + 10, m = 6 - 10

3 t^{2} - 8 t + 5 = 0

2 x^{2} - 8 x = 14

(1 - x) (1 - x) + 1 = 0

k^{2} - 3 k + 4 = 0

2 x^{2} + 9 x + 12 = 0

What are the solutions to the equation m^2-12m+26=0 ?
The solutions to the equation m^2-12m+26=0 are m=6+sqrt(10),m=6-sqrt(10)
Find the zeros of m^2-12m+26=0
The zeros of m^2-12m+26=0 are m=6+sqrt(10),m=6-sqrt(10)