What are the solutions to the equation (x^2+10)/2 =19 ?

The solutions to the equation (x^2+10)/2 =19 are x=2sqrt(7),x=-2sqrt(7)

Find the zeros of (x^2+10)/2 =19

The zeros of (x^2+10)/2 =19 are x=2sqrt(7),x=-2sqrt(7)

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\frac{x ^{2} + 10}{2} = 19

x = 27, x = - 27

Decimal Notation

x = 5.29150 \dots, x = - 5.29150 \dots

Solution steps

\frac{x ^{2} + 10}{2} = 19

Multiply both sides by

2

x^{2} + 10 = 38

Move

10

to the right side

x^{2} = 28

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 28, x = - 28

28 = 27

- 28 = - 27

x = 27, x = - 27

x^{2} - 10 x - 4

2 x^{2} + 5 x + 3

x, x^{2} + x y + 2 y^{2} = 18

x^{2} + 8 = 20

(1 + y)^{2} + y^{2} = 25

What are the solutions to the equation (x^2+10)/2 =19 ?
The solutions to the equation (x^2+10)/2 =19 are x=2sqrt(7),x=-2sqrt(7)
Find the zeros of (x^2+10)/2 =19
The zeros of (x^2+10)/2 =19 are x=2sqrt(7),x=-2sqrt(7)