What are the solutions to the equation 0=-(x-5)^2+9 ?

The solutions to the equation 0=-(x-5)^2+9 are x=8,x=2

Find the zeros of 0=-(x-5)^2+9

The zeros of 0=-(x-5)^2+9 are x=8,x=2

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0 = - (x - 5)^{2} + 9

x = 8, x = 2

Solution steps

0 = - (x - 5)^{2} + 9

Switch sides

- (x - 5)^{2} + 9 = 0

Move

9

to the right side

- (x - 5)^{2} = - 9

Divide both sides by

- 1

(x - 5)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 5 = 9 : x = 8

Solve

x - 5 = - 9 : x = 2

The solutions to the quadratic equation are:

x = 8, x = 2

x^{2} - 2 x - 6

x^{2} - 2 x + 4

x^{2} - 3 x = 2 (x + 7)

x (x + 10) = 400

x^{2} + \frac{3}{2} x + 1 = 0

What are the solutions to the equation 0=-(x-5)^2+9 ?
The solutions to the equation 0=-(x-5)^2+9 are x=8,x=2
Find the zeros of 0=-(x-5)^2+9
The zeros of 0=-(x-5)^2+9 are x=8,x=2