What are the solutions to the equation 2m^2+2/3 m=0 ?

The solutions to the equation 2m^2+2/3 m=0 are m=0,m=-1/3

Find the zeros of 2m^2+2/3 m=0

The zeros of 2m^2+2/3 m=0 are m=0,m=-1/3

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2 m^{2} + \frac{2}{3} m = 0

m = 0, m = - \frac{1}{3}

Decimal Notation

m = 0, m = - 0.33333 \dots

Solution steps

2 m^{2} + \frac{2}{3} m = 0

Multiply both sides by

3

6 m^{2} + 2 m = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 6 \cdot 0}{2 \cdot 6}

2^{2} - 4 \cdot 6 \cdot 0 = 2

m_{1, 2} = \frac{- 2 \pm 2}{2 \cdot 6}

Separate the solutions

m_{1} = \frac{- 2 + 2}{2 \cdot 6}, m_{2} = \frac{- 2 - 2}{2 \cdot 6}

m = \frac{- 2 + 2}{2 \cdot 6} : 0

m = \frac{- 2 - 2}{2 \cdot 6} : - \frac{1}{3}

The solutions to the quadratic equation are:

m = 0, m = - \frac{1}{3}

x^{7} - 64 x

\frac{3}{4} \cdot \frac{3}{5}

8 z^{2} + 20 z - 48

\frac{- π}{2}

\frac{x}{x + 1} > x

What are the solutions to the equation 2m^2+2/3 m=0 ?
The solutions to the equation 2m^2+2/3 m=0 are m=0,m=-1/3
Find the zeros of 2m^2+2/3 m=0
The zeros of 2m^2+2/3 m=0 are m=0,m=-1/3