What are the solutions to the equation k^2-6=26 ?

The solutions to the equation k^2-6=26 are k=4sqrt(2),k=-4sqrt(2)

Find the zeros of k^2-6=26

The zeros of k^2-6=26 are k=4sqrt(2),k=-4sqrt(2)

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k^{2} - 6 = 26

k = 42, k = - 42

Decimal Notation

k = 5.65685 \dots, k = - 5.65685 \dots

Solution steps

k^{2} - 6 = 26

Move

6

to the right side

k^{2} = 32

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

k = 32, k = - 32

32 = 42

- 32 = - 42

k = 42, k = - 42

(r - 3)^{2} = 25

(x - 3) (2 x + 7) = 0

2 m^{2} + 10 m - 28 = 0

4 x^{2} - 11 x = 0

x^{2} + x - 22 = 0

What are the solutions to the equation k^2-6=26 ?
The solutions to the equation k^2-6=26 are k=4sqrt(2),k=-4sqrt(2)
Find the zeros of k^2-6=26
The zeros of k^2-6=26 are k=4sqrt(2),k=-4sqrt(2)