What are the solutions to the equation x^2+97=20x ?

The solutions to the equation x^2+97=20x are x=10+sqrt(3),x=10-sqrt(3)

Find the zeros of x^2+97=20x

The zeros of x^2+97=20x are x=10+sqrt(3),x=10-sqrt(3)

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x^{2} + 97 = 20 x

x = 10 + 3, x = 10 - 3

Decimal Notation

x = 11.73205 \dots, x = 8.26794 \dots

Solution steps

x^{2} + 97 = 20 x

Move

20 x

to the left side

x^{2} + 97 - 20 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 20 x + 97 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot 97}{2 \cdot 1}

(- 20)^{2} - 4 \cdot 1 \cdot 97 = 23

x_{1, 2} = \frac{- ( - 20 ) \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 2 3}{2 \cdot 1}, x_{2} = \frac{- ( - 20 ) - 2 3}{2 \cdot 1}

x = \frac{- ( - 20 ) + 2 3}{2 \cdot 1} : 10 + 3

x = \frac{- ( - 20 ) - 2 3}{2 \cdot 1} : 10 - 3

The solutions to the quadratic equation are:

x = 10 + 3, x = 10 - 3

a^{2} + 11 a + 24 = 0

7 x = 4 x^{2} - 1

(u - 2)^{2} - 75 = 0

9 x^{2} + 6 x + 1 = 0

(m^{2} + 1) = 0

What are the solutions to the equation x^2+97=20x ?
The solutions to the equation x^2+97=20x are x=10+sqrt(3),x=10-sqrt(3)
Find the zeros of x^2+97=20x
The zeros of x^2+97=20x are x=10+sqrt(3),x=10-sqrt(3)