What are the solutions to the equation 2x^2-17x-9=0 ?

The solutions to the equation 2x^2-17x-9=0 are x=9,x=-1/2

Find the zeros of 2x^2-17x-9=0

The zeros of 2x^2-17x-9=0 are x=9,x=-1/2

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2 x^{2} - 17 x - 9 = 0

x = 9, x = - \frac{1}{2}

Decimal Notation

x = 9, x = - 0.5

Solution steps

2 x^{2} - 17 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 2 ( - 9 )}{2 \cdot 2}

(- 17)^{2} - 4 \cdot 2 (- 9) = 19

x_{1, 2} = \frac{- ( - 17 ) \pm 19}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 19}{2 \cdot 2}, x_{2} = \frac{- ( - 17 ) - 19}{2 \cdot 2}

x = \frac{- ( - 17 ) + 19}{2 \cdot 2} : 9

x = \frac{- ( - 17 ) - 19}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 9, x = - \frac{1}{2}

2 x^{2} - 3 x + 5 = 0

3 (x^{2} - 11) + 2 (x^{2} - 7) = 38

6 x^{2} - 5 = 13 x

- x^{2} + 4 x = x^{2}

6 x^{2} - 5 x - 4 = 0

What are the solutions to the equation 2x^2-17x-9=0 ?
The solutions to the equation 2x^2-17x-9=0 are x=9,x=-1/2
Find the zeros of 2x^2-17x-9=0
The zeros of 2x^2-17x-9=0 are x=9,x=-1/2