What are the solutions to the equation -4r^2-4r-8=-7 ?

The solutions to the equation -4r^2-4r-8=-7 are r=-1/2

Find the zeros of -4r^2-4r-8=-7

The zeros of -4r^2-4r-8=-7 are r=-1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 4 r^{2} - 4 r - 8 = - 7

r = - \frac{1}{2}

Decimal Notation

r = - 0.5

Solution steps

- 4 r^{2} - 4 r - 8 = - 7

Move

7

to the left side

- 4 r^{2} - 4 r - 1 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 4 ) ( - 1 )}{2 ( - 4 )}

(- 4)^{2} - 4 (- 4) (- 1) = 0

r_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 ( - 4 )}

r = \frac{- ( - 4 )}{2 ( - 4 )}

\frac{- ( - 4 )}{2 ( - 4 )} = - \frac{1}{2}

r = - \frac{1}{2}

The solution to the quadratic equation is:

r = - \frac{1}{2}

3 x^{2} - 7 x - 40 = 0

3 x^{2} + x = 10

2 x^{2} + 4 x - 16 = 0

5 x^{2} + 12 x + 2 = 7 x

7 x^{2} + x + 8 = 0

What are the solutions to the equation -4r^2-4r-8=-7 ?
The solutions to the equation -4r^2-4r-8=-7 are r=-1/2
Find the zeros of -4r^2-4r-8=-7
The zeros of -4r^2-4r-8=-7 are r=-1/2