What are the solutions to the equation x^2-4=2sqrt(3) ?

The solutions to the equation x^2-4=2sqrt(3) are x=sqrt(3)+1

Find the zeros of x^2-4=2sqrt(3)

The zeros of x^2-4=2sqrt(3) are x=sqrt(3)+1

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x^{2} - 4 = 23

x = 3 + 1

Decimal Notation

x = 2.73205 \dots

Solution steps

x^{2} - 4 = 23

Move

4

to the right side

x^{2} = 23 + 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 23 + 4, x = - 23 + 4

23 + 4 = 3 + 1

- 23 + 4 = 3 + 1

x = 3 + 1

x^{2} - 80 x + 1200 = 0

x^{2} - 9 x + 12 = 0

a^{2} + 1 6^{2} = 3 4^{2}

n^{2} - 8 n - 9 = 0

(x - 2)^{2} = - 20

What are the solutions to the equation x^2-4=2sqrt(3) ?
The solutions to the equation x^2-4=2sqrt(3) are x=sqrt(3)+1
Find the zeros of x^2-4=2sqrt(3)
The zeros of x^2-4=2sqrt(3) are x=sqrt(3)+1