What are the solutions to the equation 3x^2+7x=9 ?

The solutions to the equation 3x^2+7x=9 are x=(-7+sqrt(157))/6 ,x=(-7-sqrt(157))/6

Find the zeros of 3x^2+7x=9

The zeros of 3x^2+7x=9 are x=(-7+sqrt(157))/6 ,x=(-7-sqrt(157))/6

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3 x^{2} + 7 x = 9

x = \frac{- 7 + 157}{6}, x = \frac{- 7 - 157}{6}

Decimal Notation

x = 0.92166 \dots, x = - 3.25499 \dots

Solution steps

3 x^{2} + 7 x = 9

Move

9

to the left side

3 x^{2} + 7 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 3 ( - 9 )}{2 \cdot 3}

7^{2} - 4 \cdot 3 (- 9) = 157

x_{1, 2} = \frac{- 7 \pm 157}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 7 + 157}{2 \cdot 3}, x_{2} = \frac{- 7 - 157}{2 \cdot 3}

x = \frac{- 7 + 157}{2 \cdot 3} : \frac{- 7 + 157}{6}

x = \frac{- 7 - 157}{2 \cdot 3} : \frac{- 7 - 157}{6}

The solutions to the quadratic equation are:

x = \frac{- 7 + 157}{6}, x = \frac{- 7 - 157}{6}

x, x^{2} + y^{2} - 14 x + 2 y + 50 = 0

2 x^{2} + 6 x + 4

2 y^{2} + 5 y = - 2

x^{2} + x - 36 = 0

c (x) = 2 x^{(2)} - 188 x + 78

What are the solutions to the equation 3x^2+7x=9 ?
The solutions to the equation 3x^2+7x=9 are x=(-7+sqrt(157))/6 ,x=(-7-sqrt(157))/6
Find the zeros of 3x^2+7x=9
The zeros of 3x^2+7x=9 are x=(-7+sqrt(157))/6 ,x=(-7-sqrt(157))/6