What are the solutions to the equation 5k^2+9k+1=0 ?

The solutions to the equation 5k^2+9k+1=0 are k=(-9+sqrt(61))/(10),k=(-9-sqrt(61))/(10)

Find the zeros of 5k^2+9k+1=0

The zeros of 5k^2+9k+1=0 are k=(-9+sqrt(61))/(10),k=(-9-sqrt(61))/(10)

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5 k^{2} + 9 k + 1 = 0

k = \frac{- 9 + 61}{10}, k = \frac{- 9 - 61}{10}

Decimal Notation

k = - 0.11897 \dots, k = - 1.68102 \dots

Solution steps

5 k^{2} + 9 k + 1 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 5 \cdot 1}{2 \cdot 5}

9^{2} - 4 \cdot 5 \cdot 1 = 61

k_{1, 2} = \frac{- 9 \pm 61}{2 \cdot 5}

Separate the solutions

k_{1} = \frac{- 9 + 61}{2 \cdot 5}, k_{2} = \frac{- 9 - 61}{2 \cdot 5}

k = \frac{- 9 + 61}{2 \cdot 5} : \frac{- 9 + 61}{10}

k = \frac{- 9 - 61}{2 \cdot 5} : \frac{- 9 - 61}{10}

The solutions to the quadratic equation are:

k = \frac{- 9 + 61}{10}, k = \frac{- 9 - 61}{10}

(2 x - 3)^{2} = 100

2 x^{2} + 5 = 10 x

x, 3 x^{2} - 5 k x - 2 = 0

\frac{1}{2} x^{2} + \frac{1}{3} x - \frac{1}{6} = 0

3 x^{2} - 15 x - 18 = 0

What are the solutions to the equation 5k^2+9k+1=0 ?
The solutions to the equation 5k^2+9k+1=0 are k=(-9+sqrt(61))/(10),k=(-9-sqrt(61))/(10)
Find the zeros of 5k^2+9k+1=0
The zeros of 5k^2+9k+1=0 are k=(-9+sqrt(61))/(10),k=(-9-sqrt(61))/(10)