What are the solutions to the equation 9x^2-24x-28=0 ?

The solutions to the equation 9x^2-24x-28=0 are x=(2(2+sqrt(11)))/3 ,x=(2(2-sqrt(11)))/3

Find the zeros of 9x^2-24x-28=0

The zeros of 9x^2-24x-28=0 are x=(2(2+sqrt(11)))/3 ,x=(2(2-sqrt(11)))/3

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9 x^{2} - 24 x - 28 = 0

x = \frac{2 ( 2 + 11 )}{3}, x = \frac{2 ( 2 - 11 )}{3}

Decimal Notation

x = 3.54441 \dots, x = - 0.87774 \dots

Solution steps

9 x^{2} - 24 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 9 ( - 28 )}{2 \cdot 9}

(- 24)^{2} - 4 \cdot 9 (- 28) = 1211

x_{1, 2} = \frac{- ( - 24 ) \pm 12 11}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 12 11}{2 \cdot 9}, x_{2} = \frac{- ( - 24 ) - 12 11}{2 \cdot 9}

x = \frac{- ( - 24 ) + 12 11}{2 \cdot 9} : \frac{2 ( 2 + 11 )}{3}

x = \frac{- ( - 24 ) - 12 11}{2 \cdot 9} : \frac{2 ( 2 - 11 )}{3}

The solutions to the quadratic equation are:

x = \frac{2 ( 2 + 11 )}{3}, x = \frac{2 ( 2 - 11 )}{3}

x, x^{2} - k x + 100 = 0

a, b + 1 - ba - b a^{2} = 0

3 x + 7 - 5 x^{2} = - 4

- 3 x^{2} + 5 x + 8 = 0

x^{2} + 4 x + 29

What are the solutions to the equation 9x^2-24x-28=0 ?
The solutions to the equation 9x^2-24x-28=0 are x=(2(2+sqrt(11)))/3 ,x=(2(2-sqrt(11)))/3
Find the zeros of 9x^2-24x-28=0
The zeros of 9x^2-24x-28=0 are x=(2(2+sqrt(11)))/3 ,x=(2(2-sqrt(11)))/3