What are the solutions to the equation x^2+3x-6=4 ?

The solutions to the equation x^2+3x-6=4 are x=2,x=-5

Find the zeros of x^2+3x-6=4

The zeros of x^2+3x-6=4 are x=2,x=-5

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x^{2} + 3 x - 6 = 4

x = 2, x = - 5

Solution steps

x^{2} + 3 x - 6 = 4

Move

4

to the left side

x^{2} + 3 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 10) = 7

x_{1, 2} = \frac{- 3 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 7}{2 \cdot 1}, x_{2} = \frac{- 3 - 7}{2 \cdot 1}

x = \frac{- 3 + 7}{2 \cdot 1} : 2

x = \frac{- 3 - 7}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 2, x = - 5

4 r^{2} - 4 r - 3 = 0

x^{2} - 4 x + 8 = 4

\frac{16 - y ^{2}}{8} = \frac{y ^{2} - 48}{24}

x, 2 (x^{2} + y^{2}) 2 = 25 (x^{2} - y^{2})

\frac{1}{2} k^{2} + 53 = 5

What are the solutions to the equation x^2+3x-6=4 ?
The solutions to the equation x^2+3x-6=4 are x=2,x=-5
Find the zeros of x^2+3x-6=4
The zeros of x^2+3x-6=4 are x=2,x=-5