What are the solutions to the equation 6x^2-29x+28=0 ?

The solutions to the equation 6x^2-29x+28=0 are x= 7/2 ,x= 4/3

Find the zeros of 6x^2-29x+28=0

The zeros of 6x^2-29x+28=0 are x= 7/2 ,x= 4/3

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6 x^{2} - 29 x + 28 = 0

x = \frac{7}{2}, x = \frac{4}{3}

Decimal Notation

x = 3.5, x = 1.33333 \dots

Solution steps

6 x^{2} - 29 x + 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 29 ) \pm ( - 29 ) ^{2} - 4 \cdot 6 \cdot 28}{2 \cdot 6}

(- 29)^{2} - 4 \cdot 6 \cdot 28 = 13

x_{1, 2} = \frac{- ( - 29 ) \pm 13}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 29 ) + 13}{2 \cdot 6}, x_{2} = \frac{- ( - 29 ) - 13}{2 \cdot 6}

x = \frac{- ( - 29 ) + 13}{2 \cdot 6} : \frac{7}{2}

x = \frac{- ( - 29 ) - 13}{2 \cdot 6} : \frac{4}{3}

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = \frac{4}{3}

5 x^{2} + 8 x

3 x^{2} - 17 x = 0

x^{2} - x - 100 = 0

x^{2} = 7 0^{2} + 10 5^{2}

\frac{1}{4} x^{2} - 2 x - 12

What are the solutions to the equation 6x^2-29x+28=0 ?
The solutions to the equation 6x^2-29x+28=0 are x= 7/2 ,x= 4/3
Find the zeros of 6x^2-29x+28=0
The zeros of 6x^2-29x+28=0 are x= 7/2 ,x= 4/3