What are the solutions to the equation 32x^2-6x+9=0 ?

The solutions to the equation 32x^2-6x+9=0 are x= 3/32+i(3sqrt(31))/(32),x= 3/32-i(3sqrt(31))/(32)

Find the zeros of 32x^2-6x+9=0

The zeros of 32x^2-6x+9=0 are x= 3/32+i(3sqrt(31))/(32),x= 3/32-i(3sqrt(31))/(32)

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32 x^{2} - 6 x + 9 = 0

x = \frac{3}{32} + i \frac{3 31}{32}, x = \frac{3}{32} - i \frac{3 31}{32}

Solution steps

32 x^{2} - 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 32 \cdot 9}{2 \cdot 32}

Simplify

(- 6)^{2} - 4 \cdot 32 \cdot 9 : 631 i

x_{1, 2} = \frac{- ( - 6 ) \pm 6 31 i}{2 \cdot 32}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6 31 i}{2 \cdot 32}, x_{2} = \frac{- ( - 6 ) - 6 31 i}{2 \cdot 32}

x = \frac{- ( - 6 ) + 6 31 i}{2 \cdot 32} : \frac{3}{32} + i \frac{3 31}{32}

x = \frac{- ( - 6 ) - 6 31 i}{2 \cdot 32} : \frac{3}{32} - i \frac{3 31}{32}

The solutions to the quadratic equation are:

x = \frac{3}{32} + i \frac{3 31}{32}, x = \frac{3}{32} - i \frac{3 31}{32}

x^{2} - 3 x - 1

z^{2} - 12 z + 35 = 0

2 x (2 x + 1) = 5

x^{2} + \frac{3}{3} x + \frac{1}{3} = 0

x^{2} + 6 x + 9 = 1

What are the solutions to the equation 32x^2-6x+9=0 ?
The solutions to the equation 32x^2-6x+9=0 are x= 3/32+i(3sqrt(31))/(32),x= 3/32-i(3sqrt(31))/(32)
Find the zeros of 32x^2-6x+9=0
The zeros of 32x^2-6x+9=0 are x= 3/32+i(3sqrt(31))/(32),x= 3/32-i(3sqrt(31))/(32)