What are the solutions to the equation 6x^2-48x=0 ?

The solutions to the equation 6x^2-48x=0 are x=8,x=0

Find the zeros of 6x^2-48x=0

The zeros of 6x^2-48x=0 are x=8,x=0

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6 x^{2} - 48 x = 0

x = 8, x = 0

Solution steps

6 x^{2} - 48 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 48 ) \pm ( - 48 ) ^{2} - 4 \cdot 6 \cdot 0}{2 \cdot 6}

(- 48)^{2} - 4 \cdot 6 \cdot 0 = 48

x_{1, 2} = \frac{- ( - 48 ) \pm 48}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 48 ) + 48}{2 \cdot 6}, x_{2} = \frac{- ( - 48 ) - 48}{2 \cdot 6}

x = \frac{- ( - 48 ) + 48}{2 \cdot 6} : 8

x = \frac{- ( - 48 ) - 48}{2 \cdot 6} : 0

The solutions to the quadratic equation are:

x = 8, x = 0

- 16 t^{2} + 48 t + 160 = 160

r (r + 4) = 0

2 (x^{2} - 2 x) = 5

x^{2} - 13 + 40 = 0

- x^{2} + 2 x = 3

What are the solutions to the equation 6x^2-48x=0 ?
The solutions to the equation 6x^2-48x=0 are x=8,x=0
Find the zeros of 6x^2-48x=0
The zeros of 6x^2-48x=0 are x=8,x=0