What are the solutions to the equation 9x^2-16x-7=2x+9 ?

The solutions to the equation 9x^2-16x-7=2x+9 are x= 8/3 ,x=-2/3

Find the zeros of 9x^2-16x-7=2x+9

The zeros of 9x^2-16x-7=2x+9 are x= 8/3 ,x=-2/3

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9 x^{2} - 16 x - 7 = 2 x + 9

x = \frac{8}{3}, x = - \frac{2}{3}

Solution steps

9 x^{2} - 16 x - 7 = 2 x + 9

Move

9

to the left side

9 x^{2} - 16 x - 16 = 2 x

Move

2 x

to the left side

9 x^{2} - 18 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 9 ( - 16 )}{2 \cdot 9}

(- 18)^{2} - 4 \cdot 9 (- 16) = 30

x_{1, 2} = \frac{- ( - 18 ) \pm 30}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 30}{2 \cdot 9}, x_{2} = \frac{- ( - 18 ) - 30}{2 \cdot 9}

x = \frac{- ( - 18 ) + 30}{2 \cdot 9} : \frac{8}{3}

x = \frac{- ( - 18 ) - 30}{2 \cdot 9} : - \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{8}{3}, x = - \frac{2}{3}

72 x^{2} - 48 x = 0

4 x^{2} + 2 = 10

\frac{x ^{2}}{4} = x

5 x^{2} - 50 = - 15 x

x^{2} + 10 x = - 20

What are the solutions to the equation 9x^2-16x-7=2x+9 ?
The solutions to the equation 9x^2-16x-7=2x+9 are x= 8/3 ,x=-2/3
Find the zeros of 9x^2-16x-7=2x+9
The zeros of 9x^2-16x-7=2x+9 are x= 8/3 ,x=-2/3