What are the solutions to the equation 6x^2+3x+4=0 ?

The solutions to the equation 6x^2+3x+4=0 are x=-1/4+i(sqrt(87))/(12),x=-1/4-i(sqrt(87))/(12)

Find the zeros of 6x^2+3x+4=0

The zeros of 6x^2+3x+4=0 are x=-1/4+i(sqrt(87))/(12),x=-1/4-i(sqrt(87))/(12)

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6 x^{2} + 3 x + 4 = 0

x = - \frac{1}{4} + i \frac{87}{12}, x = - \frac{1}{4} - i \frac{87}{12}

Solution steps

6 x^{2} + 3 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 6 \cdot 4}{2 \cdot 6}

Simplify

3^{2} - 4 \cdot 6 \cdot 4 : 87 i

x_{1, 2} = \frac{- 3 \pm 87 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 3 + 87 i}{2 \cdot 6}, x_{2} = \frac{- 3 - 87 i}{2 \cdot 6}

x = \frac{- 3 + 87 i}{2 \cdot 6} : - \frac{1}{4} + i \frac{87}{12}

x = \frac{- 3 - 87 i}{2 \cdot 6} : - \frac{1}{4} - i \frac{87}{12}

The solutions to the quadratic equation are:

x = - \frac{1}{4} + i \frac{87}{12}, x = - \frac{1}{4} - i \frac{87}{12}

\frac{1}{7} x^{2} - \frac{3}{7} x = 0

(m + 1)^{2} = 0

x^{2} = 10 x + 24

3 x^{2} + 2 x = - 4

- 3 x^{2} - 6 x - 2 = 0

What are the solutions to the equation 6x^2+3x+4=0 ?
The solutions to the equation 6x^2+3x+4=0 are x=-1/4+i(sqrt(87))/(12),x=-1/4-i(sqrt(87))/(12)
Find the zeros of 6x^2+3x+4=0
The zeros of 6x^2+3x+4=0 are x=-1/4+i(sqrt(87))/(12),x=-1/4-i(sqrt(87))/(12)