What are the solutions to the equation -6x^2+7x+3=0 ?

The solutions to the equation -6x^2+7x+3=0 are x=-1/3 ,x= 3/2

Find the zeros of -6x^2+7x+3=0

The zeros of -6x^2+7x+3=0 are x=-1/3 ,x= 3/2

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- 6 x^{2} + 7 x + 3 = 0

x = - \frac{1}{3}, x = \frac{3}{2}

Solution steps

- 6 x^{2} + 7 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 6 ) \cdot 3}{2 ( - 6 )}

7^{2} - 4 (- 6) \cdot 3 = 11

x_{1, 2} = \frac{- 7 \pm 11}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 7 + 11}{2 ( - 6 )}, x_{2} = \frac{- 7 - 11}{2 ( - 6 )}

x = \frac{- 7 + 11}{2 ( - 6 )} : - \frac{1}{3}

x = \frac{- 7 - 11}{2 ( - 6 )} : \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{3}, x = \frac{3}{2}

(k - 2) x^{2} - (2 k - 1) x + (k - 1) = 0

3 x^{2} - 12 x + 24 = 0

x^{2} - 6 x - 1

- \frac{1}{3} x^{2} + \frac{4}{3} x - \frac{4}{3} = - \frac{1}{6} x^{2} + \frac{2}{3} x - \frac{13}{6}

15 x^{2} - 10 = 0

What are the solutions to the equation -6x^2+7x+3=0 ?
The solutions to the equation -6x^2+7x+3=0 are x=-1/3 ,x= 3/2
Find the zeros of -6x^2+7x+3=0
The zeros of -6x^2+7x+3=0 are x=-1/3 ,x= 3/2