What are the solutions to the equation -12x^2+4x=0 ?

The solutions to the equation -12x^2+4x=0 are x=0,x= 1/3

Find the zeros of -12x^2+4x=0

The zeros of -12x^2+4x=0 are x=0,x= 1/3

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- 12 x^{2} + 4 x = 0

x = 0, x = \frac{1}{3}

Solution steps

- 12 x^{2} + 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 12 ) \cdot 0}{2 ( - 12 )}

4^{2} - 4 (- 12) \cdot 0 = 4

x_{1, 2} = \frac{- 4 \pm 4}{2 ( - 12 )}

Separate the solutions

x_{1} = \frac{- 4 + 4}{2 ( - 12 )}, x_{2} = \frac{- 4 - 4}{2 ( - 12 )}

x = \frac{- 4 + 4}{2 ( - 12 )} : 0

x = \frac{- 4 - 4}{2 ( - 12 )} : \frac{1}{3}

The solutions to the quadratic equation are:

x = 0, x = \frac{1}{3}

(x - 9) (4 x - 8) = 0

3 x^{2} - 3 x - 126 = 0

h^{2} + 6 h + 9 = 0

10 = x^{2} + 3 x

(x + 2) (x + 5) = 4

What are the solutions to the equation -12x^2+4x=0 ?
The solutions to the equation -12x^2+4x=0 are x=0,x= 1/3
Find the zeros of -12x^2+4x=0
The zeros of -12x^2+4x=0 are x=0,x= 1/3