What are the solutions to the equation solvefor x,x^2+y^2+4y=-4 ?

The solutions to the equation solvefor x,x^2+y^2+4y=-4 are x=sqrt(-4-y^2-4y),x=-sqrt(-4-y^2-4y)

Find the zeros of solvefor x,x^2+y^2+4y=-4

The zeros of solvefor x,x^2+y^2+4y=-4 are x=sqrt(-4-y^2-4y),x=-sqrt(-4-y^2-4y)

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solve for

x, x^{2} + y^{2} + 4 y = - 4

x = - 4 - y^{2} - 4 y, x = - - 4 - y^{2} - 4 y

Solution steps

x^{2} + y^{2} + 4 y = - 4

Move

y^{2}

to the right side

x^{2} + 4 y = - 4 - y^{2}

Move

4 y

to the right side

x^{2} = - 4 - y^{2} - 4 y

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 4 - y^{2} - 4 y, x = - - 4 - y^{2} - 4 y

2 x^{2} + 16 x - 12 = 0

- 17 x^{2} + 14 + 6 x = 6 x - 7 x^{2}

y, z = (1 - 2 y) (3 y + 2)

4 x^{2} + 5 x + 10 = 0

(x + 5)^{2} = 11

What are the solutions to the equation solvefor x,x^2+y^2+4y=-4 ?
The solutions to the equation solvefor x,x^2+y^2+4y=-4 are x=sqrt(-4-y^2-4y),x=-sqrt(-4-y^2-4y)
Find the zeros of solvefor x,x^2+y^2+4y=-4
The zeros of solvefor x,x^2+y^2+4y=-4 are x=sqrt(-4-y^2-4y),x=-sqrt(-4-y^2-4y)