What are the solutions to the equation x^2-2/3 x-1/3 =0 ?

The solutions to the equation x^2-2/3 x-1/3 =0 are x=1,x=-1/3

Find the zeros of x^2-2/3 x-1/3 =0

The zeros of x^2-2/3 x-1/3 =0 are x=1,x=-1/3

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x^{2} - \frac{2}{3} x - \frac{1}{3} = 0

x = 1, x = - \frac{1}{3}

Decimal Notation

x = 1, x = - 0.33333 \dots

Solution steps

x^{2} - \frac{2}{3} x - \frac{1}{3} = 0

Multiply both sides by

3

3 x^{2} - 2 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 ( - 1 )}{2 \cdot 3}

(- 2)^{2} - 4 \cdot 3 (- 1) = 4

x_{1, 2} = \frac{- ( - 2 ) \pm 4}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 4}{2 \cdot 3}

x = \frac{- ( - 2 ) + 4}{2 \cdot 3} : 1

x = \frac{- ( - 2 ) - 4}{2 \cdot 3} : - \frac{1}{3}

The solutions to the quadratic equation are:

x = 1, x = - \frac{1}{3}

(7 + 1) (x^{2} + 2 x) = (7 + 3) (3 x + 5)

y, f = 101 + ln (e^{2 x} + z^{3}) + x e^{z} - y^{2} z

x, x^{2} + 4 y^{2} + 4 x y + 12 = 0

\frac{1}{2} x^{2} + x + 1 = 0

y^{2} - 7 = 0

What are the solutions to the equation x^2-2/3 x-1/3 =0 ?
The solutions to the equation x^2-2/3 x-1/3 =0 are x=1,x=-1/3
Find the zeros of x^2-2/3 x-1/3 =0
The zeros of x^2-2/3 x-1/3 =0 are x=1,x=-1/3