What are the solutions to the equation 5x^2+6x-25=0 ?

The solutions to the equation 5x^2+6x-25=0 are x=(-3+sqrt(134))/5 ,x=-(3+sqrt(134))/5

Find the zeros of 5x^2+6x-25=0

The zeros of 5x^2+6x-25=0 are x=(-3+sqrt(134))/5 ,x=-(3+sqrt(134))/5

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5 x^{2} + 6 x - 25 = 0

x = \frac{- 3 + 134}{5}, x = - \frac{3 + 134}{5}

Solution steps

5 x^{2} + 6 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 5 ( - 25 )}{2 \cdot 5}

6^{2} - 4 \cdot 5 (- 25) = 2134

x_{1, 2} = \frac{- 6 \pm 2 134}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 6 + 2 134}{2 \cdot 5}, x_{2} = \frac{- 6 - 2 134}{2 \cdot 5}

x = \frac{- 6 + 2 134}{2 \cdot 5} : \frac{- 3 + 134}{5}

x = \frac{- 6 - 2 134}{2 \cdot 5} : - \frac{3 + 134}{5}

The solutions to the quadratic equation are:

x = \frac{- 3 + 134}{5}, x = - \frac{3 + 134}{5}

x, 2 x^{2} - 8 x + 5 = 0

lo g_{10} (9) (2 n^{2} - 14 n) = lo g_{10} (9) (- 45 + n^{2})

6 x^{2} + 6 x - 7 = 0

2 x^{2} - 16 x = - 32

3 - y^{2} = y^{2} + 1

What are the solutions to the equation 5x^2+6x-25=0 ?
The solutions to the equation 5x^2+6x-25=0 are x=(-3+sqrt(134))/5 ,x=-(3+sqrt(134))/5
Find the zeros of 5x^2+6x-25=0
The zeros of 5x^2+6x-25=0 are x=(-3+sqrt(134))/5 ,x=-(3+sqrt(134))/5