What are the solutions to the equation -3x^2+x+6=0 ?

The solutions to the equation -3x^2+x+6=0 are x=-(-1+sqrt(73))/6 ,x=(1+sqrt(73))/6

Find the zeros of -3x^2+x+6=0

The zeros of -3x^2+x+6=0 are x=-(-1+sqrt(73))/6 ,x=(1+sqrt(73))/6

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- 3 x^{2} + x + 6 = 0

x = - \frac{- 1 + 73}{6}, x = \frac{1 + 73}{6}

Solution steps

- 3 x^{2} + x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 3 ) \cdot 6}{2 ( - 3 )}

1^{2} - 4 (- 3) \cdot 6 = 73

x_{1, 2} = \frac{- 1 \pm 73}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 1 + 73}{2 ( - 3 )}, x_{2} = \frac{- 1 - 73}{2 ( - 3 )}

x = \frac{- 1 + 73}{2 ( - 3 )} : - \frac{- 1 + 73}{6}

x = \frac{- 1 - 73}{2 ( - 3 )} : \frac{1 + 73}{6}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 73}{6}, x = \frac{1 + 73}{6}

- 3 x^{2} + x + 5 = 0

a - 7 = a^{2} - 9

y^{2} + 3 y = 28

2 k (k + 3) = - 9

2 x^{2} + 8 x - 1 = 0

What are the solutions to the equation -3x^2+x+6=0 ?
The solutions to the equation -3x^2+x+6=0 are x=-(-1+sqrt(73))/6 ,x=(1+sqrt(73))/6
Find the zeros of -3x^2+x+6=0
The zeros of -3x^2+x+6=0 are x=-(-1+sqrt(73))/6 ,x=(1+sqrt(73))/6