What are the solutions to the equation x^2-3sqrt(2)x-8=0 ?

The solutions to the equation x^2-3sqrt(2)x-8=0 are x=4sqrt(2),x=-sqrt(2)

Find the zeros of x^2-3sqrt(2)x-8=0

The zeros of x^2-3sqrt(2)x-8=0 are x=4sqrt(2),x=-sqrt(2)

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x^{2} - 32 x - 8 = 0

x = 42, x = - 2

Decimal Notation

x = 5.65685 \dots, x = - 1.41421 \dots

Solution steps

x^{2} - 32 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 2 ) \pm ( - 3 2 ) ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

(- 32)^{2} - 4 \cdot 1 \cdot (- 8) = 52

x_{1, 2} = \frac{- ( - 3 2 ) \pm 5 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 2 ) + 5 2}{2 \cdot 1}, x_{2} = \frac{- ( - 3 2 ) - 5 2}{2 \cdot 1}

x = \frac{- ( - 3 2 ) + 5 2}{2 \cdot 1} : 42

x = \frac{- ( - 3 2 ) - 5 2}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 42, x = - 2

- x^{2} + 5 x - 3 = 0

x + 10 x^{2} - 12 x = x^{2} + 2 x

x^{2} - \frac{9}{2} x - \frac{24}{5} = 0

x, x^{2} + y^{2} - 4 x + 12 y + 40 = 0

r, (x - h)^{2} + (y - h)^{2} = r^{2}

What are the solutions to the equation x^2-3sqrt(2)x-8=0 ?
The solutions to the equation x^2-3sqrt(2)x-8=0 are x=4sqrt(2),x=-sqrt(2)
Find the zeros of x^2-3sqrt(2)x-8=0
The zeros of x^2-3sqrt(2)x-8=0 are x=4sqrt(2),x=-sqrt(2)