What are the solutions to the equation 12x^2+6=17x ?

The solutions to the equation 12x^2+6=17x are x= 3/4 ,x= 2/3

Find the zeros of 12x^2+6=17x

The zeros of 12x^2+6=17x are x= 3/4 ,x= 2/3

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12 x^{2} + 6 = 17 x

x = \frac{3}{4}, x = \frac{2}{3}

Decimal Notation

x = 0.75, x = 0.66666 \dots

Solution steps

12 x^{2} + 6 = 17 x

Move

17 x

to the left side

12 x^{2} + 6 - 17 x = 0

Write in the standard form

a x^{2} + b x + c = 0

12 x^{2} - 17 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 12 \cdot 6}{2 \cdot 12}

(- 17)^{2} - 4 \cdot 12 \cdot 6 = 1

x_{1, 2} = \frac{- ( - 17 ) \pm 1}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 1}{2 \cdot 12}, x_{2} = \frac{- ( - 17 ) - 1}{2 \cdot 12}

x = \frac{- ( - 17 ) + 1}{2 \cdot 12} : \frac{3}{4}

x = \frac{- ( - 17 ) - 1}{2 \cdot 12} : \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{3}{4}, x = \frac{2}{3}

0 = - 4.9 x^{2} + 24.5 x + 9.5

y, y^{2} = 11 y - 28

1 0^{2} + x^{2} = 1 5^{2}

x, x^{2} = 2 y^{2}

11 e^{2} + 5 = 7 e

What are the solutions to the equation 12x^2+6=17x ?
The solutions to the equation 12x^2+6=17x are x= 3/4 ,x= 2/3
Find the zeros of 12x^2+6=17x
The zeros of 12x^2+6=17x are x= 3/4 ,x= 2/3