What are the solutions to the equation 6x^2-37x+6=0 ?

The solutions to the equation 6x^2-37x+6=0 are x=6,x= 1/6

Find the zeros of 6x^2-37x+6=0

The zeros of 6x^2-37x+6=0 are x=6,x= 1/6

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6 x^{2} - 37 x + 6 = 0

x = 6, x = \frac{1}{6}

Decimal Notation

x = 6, x = 0.16666 \dots

Solution steps

6 x^{2} - 37 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 37 ) \pm ( - 37 ) ^{2} - 4 \cdot 6 \cdot 6}{2 \cdot 6}

(- 37)^{2} - 4 \cdot 6 \cdot 6 = 35

x_{1, 2} = \frac{- ( - 37 ) \pm 35}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 37 ) + 35}{2 \cdot 6}, x_{2} = \frac{- ( - 37 ) - 35}{2 \cdot 6}

x = \frac{- ( - 37 ) + 35}{2 \cdot 6} : 6

x = \frac{- ( - 37 ) - 35}{2 \cdot 6} : \frac{1}{6}

The solutions to the quadratic equation are:

x = 6, x = \frac{1}{6}

y^{2} + 7 y - 8 = 0

\frac{1}{9} = x^{2}

w^{2} + 4 w - 12 = 0

k^{2} + 3 k = 0

- x^{2} - 100 = 0

What are the solutions to the equation 6x^2-37x+6=0 ?
The solutions to the equation 6x^2-37x+6=0 are x=6,x= 1/6
Find the zeros of 6x^2-37x+6=0
The zeros of 6x^2-37x+6=0 are x=6,x= 1/6