What are the solutions to the equation r^2-6r=0 ?

The solutions to the equation r^2-6r=0 are r=6,r=0

Find the zeros of r^2-6r=0

The zeros of r^2-6r=0 are r=6,r=0

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r^{2} - 6 r = 0

r = 6, r = 0

Solution steps

r^{2} - 6 r = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 0 = 6

r_{1, 2} = \frac{- ( - 6 ) \pm 6}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 6 ) + 6}{2 \cdot 1}, r_{2} = \frac{- ( - 6 ) - 6}{2 \cdot 1}

r = \frac{- ( - 6 ) + 6}{2 \cdot 1} : 6

r = \frac{- ( - 6 ) - 6}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

r = 6, r = 0

6 = x^{2}

x (x - 2) + 3 (x - 2) = 0

3 x^{2} + 8 x - 7 = 4

x, y + 3 x^{2} y = x^{2}

x, x^{2} - 4 x - 5 = 0

What are the solutions to the equation r^2-6r=0 ?
The solutions to the equation r^2-6r=0 are r=6,r=0
Find the zeros of r^2-6r=0
The zeros of r^2-6r=0 are r=6,r=0