What are the solutions to the equation 5v^2+3=3v ?

The solutions to the equation 5v^2+3=3v are v= 3/10+i(sqrt(51))/(10),v= 3/10-i(sqrt(51))/(10)

Find the zeros of 5v^2+3=3v

The zeros of 5v^2+3=3v are v= 3/10+i(sqrt(51))/(10),v= 3/10-i(sqrt(51))/(10)

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5 v^{2} + 3 = 3 v

v = \frac{3}{10} + i \frac{51}{10}, v = \frac{3}{10} - i \frac{51}{10}

Solution steps

5 v^{2} + 3 = 3 v

Move

3 v

to the left side

5 v^{2} + 3 - 3 v = 0

Write in the standard form

a x^{2} + b x + c = 0

5 v^{2} - 3 v + 3 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 5 \cdot 3}{2 \cdot 5}

Simplify

(- 3)^{2} - 4 \cdot 5 \cdot 3 : 51 i

v_{1, 2} = \frac{- ( - 3 ) \pm 51 i}{2 \cdot 5}

Separate the solutions

v_{1} = \frac{- ( - 3 ) + 51 i}{2 \cdot 5}, v_{2} = \frac{- ( - 3 ) - 51 i}{2 \cdot 5}

v = \frac{- ( - 3 ) + 51 i}{2 \cdot 5} : \frac{3}{10} + i \frac{51}{10}

v = \frac{- ( - 3 ) - 51 i}{2 \cdot 5} : \frac{3}{10} - i \frac{51}{10}

The solutions to the quadratic equation are:

v = \frac{3}{10} + i \frac{51}{10}, v = \frac{3}{10} - i \frac{51}{10}

(x - 6) (x - 5) = 0

- x^{2} + 4 x - 3 = 0

3 y^{2} - 24 y + 36 = 0

3 x^{2} - 4 (x - 2) = 0

y^{2} - 2 y = 4

What are the solutions to the equation 5v^2+3=3v ?
The solutions to the equation 5v^2+3=3v are v= 3/10+i(sqrt(51))/(10),v= 3/10-i(sqrt(51))/(10)
Find the zeros of 5v^2+3=3v
The zeros of 5v^2+3=3v are v= 3/10+i(sqrt(51))/(10),v= 3/10-i(sqrt(51))/(10)