What are the solutions to the equation (3x+2)(2x-1)=13 ?

The solutions to the equation (3x+2)(2x-1)=13 are x= 3/2 ,x=-5/3

Find the zeros of (3x+2)(2x-1)=13

The zeros of (3x+2)(2x-1)=13 are x= 3/2 ,x=-5/3

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(3 x + 2) (2 x - 1) = 13

x = \frac{3}{2}, x = - \frac{5}{3}

Solution steps

(3 x + 2) (2 x - 1) = 13

Expand

(3 x + 2) (2 x - 1) : 6 x^{2} + x - 2

6 x^{2} + x - 2 = 13

Move

13

to the left side

6 x^{2} + x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 6 ( - 15 )}{2 \cdot 6}

1^{2} - 4 \cdot 6 (- 15) = 19

x_{1, 2} = \frac{- 1 \pm 19}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 1 + 19}{2 \cdot 6}, x_{2} = \frac{- 1 - 19}{2 \cdot 6}

x = \frac{- 1 + 19}{2 \cdot 6} : \frac{3}{2}

x = \frac{- 1 - 19}{2 \cdot 6} : - \frac{5}{3}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - \frac{5}{3}

2 x^{2} + 11 x - 12 = 0

y^{2} = 1033

y (2 y + 3) = 5

- 10 - 4 x^{2} = - 46

- 5 + 2 x^{2} = - 7 x + x^{2} - 4

What are the solutions to the equation (3x+2)(2x-1)=13 ?
The solutions to the equation (3x+2)(2x-1)=13 are x= 3/2 ,x=-5/3
Find the zeros of (3x+2)(2x-1)=13
The zeros of (3x+2)(2x-1)=13 are x= 3/2 ,x=-5/3