What are the solutions to the equation -x\times (-x-2)-(x-1/2)\times 2x+8=x^2-1 ?

The solutions to the equation -x\times (-x-2)-(x-1/2)\times 2x+8=x^2-1 are x=-3/2 ,x=3

Find the zeros of -x\times (-x-2)-(x-1/2)\times 2x+8=x^2-1

The zeros of -x\times (-x-2)-(x-1/2)\times 2x+8=x^2-1 are x=-3/2 ,x=3

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- x \cdot (- x - 2) - (x - \frac{1}{2}) \cdot 2 x + 8 = x^{2} - 1

x = - \frac{3}{2}, x = 3

Decimal

x = - 1.5, x = 3

Solution steps

- x (- x - 2) - (x - \frac{1}{2}) \cdot 2 x + 8 = x^{2} - 1

Expand

- x (- x - 2) - (x - \frac{1}{2}) \cdot 2 x + 8 : - x^{2} + 3 x + 8

- x^{2} + 3 x + 8 = x^{2} - 1

Move

1

to the left side

- x^{2} + 3 x + 9 = x^{2}

Move

x^{2}

to the left side

- 2 x^{2} + 3 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 2 ) \cdot 9}{2 ( - 2 )}

3^{2} - 4 (- 2) \cdot 9 = 9

x_{1, 2} = \frac{- 3 \pm 9}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 3 + 9}{2 ( - 2 )}, x_{2} = \frac{- 3 - 9}{2 ( - 2 )}

x = \frac{- 3 + 9}{2 ( - 2 )} : - \frac{3}{2}

x = \frac{- 3 - 9}{2 ( - 2 )} : 3

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = 3

x^{2} + 8 x = - 9

4 x^{2} - 5 x - 5 = 0

\frac{1}{5} q^{2} + 10 = 86 - 6 q - 3 q^{2}

4 x^{2} - 5 x - 4 = 0

(x - 1) (x - 2) = 12

What are the solutions to the equation -x\times (-x-2)-(x-1/2)\times 2x+8=x^2-1 ?
The solutions to the equation -x\times (-x-2)-(x-1/2)\times 2x+8=x^2-1 are x=-3/2 ,x=3
Find the zeros of -x\times (-x-2)-(x-1/2)\times 2x+8=x^2-1
The zeros of -x\times (-x-2)-(x-1/2)\times 2x+8=x^2-1 are x=-3/2 ,x=3