What are the solutions to the equation x^2+x+13=0 ?

The solutions to the equation x^2+x+13=0 are x=-1/2+i(sqrt(51))/2 ,x=-1/2-i(sqrt(51))/2

Find the zeros of x^2+x+13=0

The zeros of x^2+x+13=0 are x=-1/2+i(sqrt(51))/2 ,x=-1/2-i(sqrt(51))/2

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x^{2} + x + 13 = 0

x = - \frac{1}{2} + i \frac{51}{2}, x = - \frac{1}{2} - i \frac{51}{2}

Solution steps

x^{2} + x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 13 : 51 i

x_{1, 2} = \frac{- 1 \pm 51 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 51 i}{2 \cdot 1}, x_{2} = \frac{- 1 - 51 i}{2 \cdot 1}

x = \frac{- 1 + 51 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{51}{2}

x = \frac{- 1 - 51 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{51}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{51}{2}, x = - \frac{1}{2} - i \frac{51}{2}

s^{2} + 6 s + 10

- 0.004 x^{2} + 250 = 0.0024 x^{2} + 0.04 x + 100

s^{2} + 6 s + 34

(x^{2} - 5 x + 9) \cdot lo g_{10} (2) + lo g_{10} (125) = 3

p^{2} = 2

What are the solutions to the equation x^2+x+13=0 ?
The solutions to the equation x^2+x+13=0 are x=-1/2+i(sqrt(51))/2 ,x=-1/2-i(sqrt(51))/2
Find the zeros of x^2+x+13=0
The zeros of x^2+x+13=0 are x=-1/2+i(sqrt(51))/2 ,x=-1/2-i(sqrt(51))/2